document.write( "Question 86692: I have been working on this one till my head hurts and I made myself more confused than needs to be.\r
\n" ); document.write( "\n" ); document.write( "A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100 lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture? \n" ); document.write( "

Algebra.Com's Answer #62702 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100 lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture?
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\n" ); document.write( "Here's an easy way to understand it:
\n" ); document.write( "Let x = no. of pounds of $12 coffee:
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\n" ); document.write( "The problems states the the resulting amt will be 100 lb, therefore:
\n" ); document.write( "(100-x) = no. of pounds of $9 coffee
\n" ); document.write( ":
\n" ); document.write( "A simple equation:
\n" ); document.write( "9(100-x) + 12x = 11.25(100)
\n" ); document.write( ":
\n" ); document.write( "900 - 9x + 12x = 1125
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\n" ); document.write( "3x = 1125 - 900
\n" ); document.write( ":
\n" ); document.write( "3x = 225
\n" ); document.write( ":
\n" ); document.write( "x = 225/3
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\n" ); document.write( "x = 75 lb of $12 coffee, obviously, then we need 25 lb of $9 coffee
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\n" ); document.write( "Check our solution:
\n" ); document.write( "9(25) + 12(75) =
\n" ); document.write( " 225 + 900 = 1125, which is 11.25*100 \n" ); document.write( "

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