document.write( "Question 1011361: HEMISPHERE ON HEMISPHERE.THE LARGE ONE HAS DIAMETER 22CM SMALLER 12CM WHAT IS THE TOTAL SURFACE AREA.\r
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Algebra.Com's Answer #626990 by MathLover1(20855)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "You must know that the surface area of a sphere is \"4pi%2Ar%5E2\".\r
\n" ); document.write( "\n" ); document.write( "A \"hemisphere\" is \"half\" of a \"sphere\", this must mean that the curved surface area of a hemisphere is the surface area of a sphere divide by \"2\".
\n" ); document.write( "That is \"4pi%2Ar%5E2%2F2\" which gives the following expression: \r
\n" ); document.write( "\n" ); document.write( " \"Curved_+Surface_+Area+=2pi%2Ar%5E2\" \r
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\n" ); document.write( "\n" ); document.write( "Total Surface Area of Hemisphere includes the circular base below the curve and its area is \"r%5E2%2Api+\", so\r
\n" ); document.write( "\n" ); document.write( "\"Total+_Surface+_Area+_of_+Hemisphere+=2pi%2Ar%5E2%2Br%5E2%2Api+\"\r
\n" ); document.write( "\n" ); document.write( "if the large has diameter \"22cm\", then its radius is \"11cm\", and\r
\n" ); document.write( "\n" ); document.write( "\"Total+_Surface+_Area+_of_+larger_Hemisphere+=2pi%2A%2811cm%29%5E2%2B%2811cm%29%5E2%2Api+\"\r
\n" ); document.write( "\n" ); document.write( "\"Total+_Surface+_Area+_of_+larger_Hemisphere+=2pi%2A121cm%5E2%2B121cm%5E2%2Api+\"\r
\n" ); document.write( "\n" ); document.write( "\"Total+_Surface+_Area+_of_larger_+Hemisphere+=pi%2A242cm%5E2%2B121cm%5E2%2Api+\"\r
\n" ); document.write( "\n" ); document.write( "\"Total+_Surface+_Area+_of_larger_+Hemisphere+=363cm%5E2%2Api+\"\r
\n" ); document.write( "\n" ); document.write( "if their bases touching each other, then the area of the bases of smaller hemisphere will be already included in the area of the bases of greater hemisphere; so for smaller hemisphere we will need only curved surface area \r
\n" ); document.write( "\n" ); document.write( "and if the smaller has diameter \"12cm\", then its radius is \"6cm\", and\r
\n" ); document.write( "\n" ); document.write( "\"Curved_+Surface_+Area_of_smaller_+Hemisphere++=2pi%2A%286cm%29%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "\"Curved_+Surface_+Area_of_smaller_+Hemisphere++=2pi%2A36cm%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "\"Curved_+Surface_+Area_of_smaller_+Hemisphere++=72cm%5E2%2Api+\"\r
\n" ); document.write( "\n" ); document.write( "and, total surface area of both hemispheres will be:\r
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