document.write( "Question 1011338: If x can take any whole number value from 1 to 10, find the smallest possible value of x2-8x+25. \n" ); document.write( "
Algebra.Com's Answer #626948 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the smallest possible value a quadratic in the form of ax^2 + bx + c = 0 would be at x = -b/2a.\r
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\n" ); document.write( "\n" ); document.write( "your equation of x^2 -8x + 25 is already in that form when you set it equal to 0.\r
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\n" ); document.write( "\n" ); document.write( "a = coefficient of x^2 term = 1
\n" ); document.write( "b = coefficient of x term = -8
\n" ); document.write( "c = coefficient of c term = 25\r
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\n" ); document.write( "\n" ); document.write( "x = -b/2a = -(-8)/(2*1) = 8/2 = 4\r
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\n" ); document.write( "\n" ); document.write( "when x = 4, y = x^2 - 8x + 25 becomes y = 4^2 - 8*4 + 25 which becomes 16 - 32 + 25 which becomes 9.\r
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\n" ); document.write( "\n" ); document.write( "the smallest value of x^2-8x+25 would be equal to 9.\r
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\n" ); document.write( "\n" ); document.write( "here's what the graph looks like.\r
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