document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011319>Question 1011319</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 12 liters of 50% solution for a lab experiment. The stockroomconly has 40% and 70% solution. How much of each should be mixed together to make 12 liters of a 50% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626934 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626934\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y= 12 and if we want to know just x, we subtract y:<BR>\n" );
document.write( "x+y-y= 12-y<BR>\n" );
document.write( "x= 12-y We'll use this value for x next.<BR>\n" );
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document.write( ".40x+.70y= .50(12) Substitute for x:<BR>\n" );
document.write( ".40(12-y)+.70y= .50(12)<BR>\n" );
document.write( "4.8-.40y+.70y= 6 Subtract 4.8 on both sides and add/subtract y on left:<BR>\n" );
document.write( ".30y= 1.2 Divide both sides by .30:<BR>\n" );
document.write( "y= 4 He needs 4 liters of the 70% solution and:<BR>\n" );
document.write( "12-4= 8 liters of the 40% solution<BR>\n" );
document.write( "J\r<BR>\n" );
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document.write( " </SPAN>\n" );
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