document.write( "Question 1011293: the equation of a circle is given by x^2 + y^2 - 10x -8y + 25 = o
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Algebra.Com's Answer #626913 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "the equation of a circle is given by x^2 + y^2 - 10x -8y + 25 = o
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document.write( "Complete the squares:\r\n" );
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document.write( "\"x%5E2+%2B+y%5E2+-+10x+-8y+%2B+25\" = \"%28x-5%29%5E2\" + \"%28y-4%29%5E2\" - \"16\". \r\n" );
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document.write( "Therefore, the equation \r\n" );
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document.write( "\"x%5E2+%2B+y%5E2+-+10x+-8y+%2B+25\" = \"0\"\r\n" );
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document.write( "is equivalent to the equation\r\n" );
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document.write( "\"%28x-5%29%5E2\" + \"%28y-4%29%5E2\" = \"4%5E2\".\r\n" );
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document.write( "This is the equation of the circle with the center at the point (x,y) = (5,4) and the radius of 4 units.\r\n" );
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document.write( "Since y-coordinate of the center is 4 and the radius of the circle equals 4 too, the circle touches the x-axis.\r\n" );
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document.write( "The coordinate of the contact point is (5,0).\r\n" );
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document.write( "Comment from student: but please how did u get the coordinates to be (5,0)?\r\n" );
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document.write( "My response: The center of the circle is at the point (5,4) and the radius is 4.\r\n" );
document.write( "Obviously, the circle touches x-axis and the contact point is (5,0).\r\n" );
document.write( "Zero is the y-coordinate of the contact point.\r\n" );
document.write( "Make a sketch.\r\n" );
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