document.write( "Question 1011286: The rate of a boat in still water is 7km/hr. If the boat can travel 30km downstream in the same time it can travel 12 km upstream, find the rate of the river current.\r
\n" ); document.write( "\n" ); document.write( "Is there a formula for this kind of question? Please help!
\n" ); document.write( "

Algebra.Com's Answer #626898 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
It's not really a \"formula\"
\n" ); document.write( "It's just catching on to a method
\n" ); document.write( "Just use [ distance ] = [ rate ] x [ time ]
\n" ); document.write( "--------------------------
\n" ); document.write( "Let \"+c+\" = the rate of the current in km/hr
\n" ); document.write( "\"+7+%2B+c+\" = rate of the boat going downstream
\n" ); document.write( "\"+7+-+c+\" = rate of the boat going upstream
\n" ); document.write( "Let \"+t+\" = time in hrs for going either upstream or downstream
\n" ); document.write( "------------------------------------
\n" ); document.write( "Equation for going downstream:
\n" ); document.write( "(1) \"+30+=+%28+7+%2B+c+%29%2At+\"
\n" ); document.write( "Equation for going upstream:
\n" ); document.write( "(2) \"+12+=+%28+7+-+c+%29%2At+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "(1) \"+t+=+30+%2F+%28+7+%2B+c+%29+\"
\n" ); document.write( "Substitute this into (2)
\n" ); document.write( "(2) \"+12+=+%28+7+-+c+%29%2A%28+30+%2F+%28+7+%2B+c+%29+%29+\"
\n" ); document.write( "Multiply both sides by \"+7+%2B+c+\"
\n" ); document.write( "(2) \"+12%2A%28+7+%2B+c+%29+=+30%2A%28+7+-+c+%29+\"
\n" ); document.write( "(2) \"+84+%2B+12c+=+210+-+30c+\"
\n" ); document.write( "(2) \"+42c+=+126+\"
\n" ); document.write( "(2) \"+c+=+3+\"
\n" ); document.write( "The rate of the current is 3 km/hr
\n" ); document.write( "-----------------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+30+=+%28+7+%2B+c+%29%2At+\"
\n" ); document.write( "(1) \"+30+=+%28+7+%2B3+%29%2At+\"
\n" ); document.write( "(1) \"+30+=+10t+\"
\n" ); document.write( "(1) \"+t+=+3+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+12+=+%28+7+-+c+%29%2At+\"
\n" ); document.write( "(2) \"+12+=+%28+7+-+3+%29%2At+\"
\n" ); document.write( "(2) \"+12+=+4t+\"
\n" ); document.write( "(2) \"+t+=+3+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );