document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009225>Question 1009225</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Part 2: Using these similarities and differences, how would you transform f(x) = 2 sin(2x - &#960;) + 3 into a cosine function in the form f(x) = a cos(bx - c) + d? please use details </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626872 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using these similarities and differences, how would you transform <BR>\n" );
document.write( "f(x) = 2 sin(2x - &#960;) + 3 into a cosine function in the form<BR>\n" );
document.write( "f(x) = a cos(bx - c) + d?<BR>\n" );
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document.write( "Note:: sin(x) = cos((pi/2)-x)<BR>\n" );
document.write( "So, sin(2x-pi) = cos((pi/2)-(x-(pi/2)) = cos(pi-x)\r<BR>\n" );
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document.write( "Ans:: 2cos(pi-x)+3 OR 2cos(-x-(-pi)) + 3\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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