document.write( "Question 1011231: Find the mean, variance, and standard deviation of the probability distribution,
\n" ); document.write( "Complete parts (a) and (b) using the probability distribution below.\r
\n" ); document.write( "\n" ); document.write( "The number of overtime hours worked in one week per employee overtime hours.\r
\n" ); document.write( "\n" ); document.write( " 0 1 2 3 4 5 6\r
\n" ); document.write( "\n" ); document.write( "Probability 0.032 0.058 0.169 0.296 0.228 0.143 0.074 \n" ); document.write( "
Algebra.Com's Answer #626837 by Boreal(15235)\"\" \"About 
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0*0.032=0
\n" ); document.write( "1*0.058=0.058
\n" ); document.write( "2*0.169=0.338
\n" ); document.write( "3*0.296=0.888
\n" ); document.write( "4*0.228=0.912
\n" ); document.write( "5*0.143=0.715
\n" ); document.write( "6*0.074=0.444
\n" ); document.write( "Sum is 3.355, and that is the mean in hours\r
\n" ); document.write( "\n" ); document.write( "variance is{ (x^2)*p(x)}-mu^2
\n" ); document.write( "0*0.032=0
\n" ); document.write( "1*0.058=0.058
\n" ); document.write( "4*0.169=0.676
\n" ); document.write( "9*0.296=2.664
\n" ); document.write( "16*0.228=3.648
\n" ); document.write( "25*0.143=3.575
\n" ); document.write( "36*0.074=2.664
\n" ); document.write( "Sum is 13.285. Subtact mu^2=11.256=2.029=variance in hours ^2
\n" ); document.write( "1.4244 is standard deviation in hours.
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