document.write( "Question 1011155: Twelve people show up to help out at a concession stand. Two people are needed to remain with the cash box, four people are needed to make the food, and the rest would work with the customers. In how many different ways can these jobs be assigned?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #626832 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
You can start picking in any order, and the result should be the same.
\n" ); document.write( "In how many ways can you pick a set of \"2\" cashiers from your set of \"12\" volunteers?
\n" ); document.write( "\"12%2A11%2F%281%2A2%29=6%2A11=66\" .
\n" ); document.write( "After you decided who would be your \"2\" cashiers,
\n" ); document.write( "there are \"12-2=10\" volunteers left to choose from.
\n" ); document.write( "In how many ways can you pick a set of \"4\" food-preparers from your set of \"10\" available volunteers?
\n" ); document.write( "\"10%2A9%2A8%2A7%2F%281%2A2%2A3%2A4%29=10%2A9%2A7%2F3=10%2A3%2A7=210\" .
\n" ); document.write( "For each of the \"66\" possible cashiers sets choices,
\n" ); document.write( "you have \"210\" possible choices for the set of food-preparers,
\n" ); document.write( "for a total of \"66%2A210=highlight%2813860%29\" assignment choices.
\n" ); document.write( "
\n" ); document.write( "
\n" );