document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011170>Question 1011170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mower A can mow the village park in 3 hours and Mower B can mow the park in 2 hours. At 7 am Mower A began to mow the park and was joined by Mower B at 7:30 am. At what time was the job completed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626759 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mower A does 1/3 of the village park every hour.<BR>\n" );
document.write( "mower B does 1/2<BR>\n" );
document.write( "x=number of hours for mower a<BR>\n" );
document.write( "x/3 + (x-0.5/2=1, where 1 is the whole park<BR>\n" );
document.write( "2x+3x-1.5=6<BR>\n" );
document.write( "5x=7.5<BR>\n" );
document.write( "x=1.5 hours<BR>\n" );
document.write( "done at 8:30 am<BR>\n" );
document.write( "1.5/3 for mower a (50%)<BR>\n" );
document.write( "1/2 for mower B is (50%)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );