document.write( "Question 1011120: Solve the four equations simultaneously ,\r
\n" ); document.write( "\n" ); document.write( "2a+c=0
\n" ); document.write( "3a+2b+d=3
\n" ); document.write( "a+3b+c=2
\n" ); document.write( "b+d= -1
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #626694 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "Solve the four equations simultaneously ,\r
\n" ); document.write( "\n" ); document.write( "2a+c=0
\n" ); document.write( "3a+2b+d=3
\n" ); document.write( "a+3b+c=2
\n" ); document.write( "b+d= -1
\n" ); document.write( "

2a      + c         =   0 ----- eq (i)
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document.write( "3a + 2b        + d  =   3 ----- eq (ii)
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document.write( " a + 3b + c         =   2 ----- eq (iii)
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document.write( "      b         + d = - 1 ----- eq (iv)\r
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document.write( "   a - 3b = - 2 ------ Subtracting eq (iii) from eq (i) -------- eq (v)
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document.write( "  3a +  b =   4 ------ Subtracting eq (iv) from eq (ii) -------- eq (vi)
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document.write( "– 3a + 9b =   6 ------ Multiplying eq (v) by – 3 ------- eq (vii)  
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document.write( "      10b =  10 ------ Adding eqs (vii) & (vi)
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document.write( "        b = , or 1\r
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document.write( "a - 3(1) = - 2 ----- Substituting 1 for b in eq (v)
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document.write( "a – 3 = - 2
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document.write( "a = - 2 + 3, or 1\r
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document.write( "1 + d = - 1 -------- Substituting 1 for b in eq (iv)
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document.write( "d = - 1 – 1, or - 2\r
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document.write( "2(1) + c = 0 ------- Substituting 1 for a in eq (i)
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document.write( "2 + c = 0
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document.write( "c = - 2\r
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