document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011086>Question 1011086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi,\r<BR>\n" );
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document.write( "I would like to say thank you in advance.\r<BR>\n" );
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document.write( "My question is:\r<BR>\n" );
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document.write( "A certain punch press requires 2 hours longer to stamp a box of parts than does a newer-model punch press. After the old press has been punching a box of parts for 5 hours, it is joined by the new machine. Together, they finish the box of parts in 3 additional hours. How long does it take each machine, working alone, to punch a box of parts.\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626630 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> new model takes x hours to do the whole thing.  In 1 hour, it does 1/x<BR>\n" );
document.write( "old model takes x+2 hours to do the whole thing.  In 1 hour, it does 1/(x+2)<BR>\n" );
document.write( "8/(x+2)+3/x=1<BR>\n" );
document.write( "x(x+2)=8x+3(x+2), clearing fractions by multiplying everything by x(x+2)<BR>\n" );
document.write( "x^2+2x=11x+6<BR>\n" );
document.write( "x^2-9x-6=0<BR>\n" );
document.write( "x=(1/2)(9+sqrt(81+24); sqrt 105=10.25<BR>\n" );
document.write( "x=(1/2)19.25=9.63 hours, only positive root. That is new punch press.  The old one takes 11.63 hours.<BR>\n" );
document.write( "After 5 hours,<BR>\n" );
document.write( "old punch pass has done 8/11.63=0.688 of the job<BR>\n" );
document.write( "the new one does 3/9.63 = 0.311 of the job\r<BR>\n" );
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