document.write( "Question 86642This question is from textbook algebra structure and method
\n" ); document.write( ": I can't seem to figure out how check to make the answer is right.
\n" ); document.write( "3a/7=-2/5
\n" ); document.write( "a=-14/15
\n" ); document.write( "could you help me. Thank you so much!!
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Algebra.Com's Answer #62661 by tutorcecilia(2152)\"\" \"About 
You can put this solution on YOUR website!
Check by plugging (a=-14/15) back into the original equation and solve:
\n" ); document.write( "\"%283a%2F7%29\"= \"%28-2%2F5%29\"
\n" ); document.write( "\"%283%28-14%2F15%29%2F7%29\" = \"%28-2%2F5%29\"
\n" ); document.write( "\"%28%28-14%2F5%29%2F%287%29%29\" = \"%28-2%2F5%29\"
\n" ); document.write( "\"%28%287%2F1%29%28-14%2F5%29%2F%287%29%29\"= \"%28%287%2F1%29%28-2%2F5%29%29\" [multiply each side by the reciprocal of (1/7)]
\n" ); document.write( "\"%28-14%2F15%29\" = \"%28-14%2F15%29\" [checks out]
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