document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008776>Question 1008776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need help please.. Thanks<BR>\n" );
document.write( "How many  of this succession terms -12,-7,-2,3,8...need to be sum so the total will be 105 ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626607 by </B><A HREF=/tutors/aboutme.mpl?userid=farohw><B>farohw(175)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=farohw><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=farohw><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "In this arithmetic sequence, each term is added by 5 which is the common difference. To obtain a sum of 105:\r<BR>\n" );
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document.write( "-12, -7, -2, 3, 8, 13, 18, 23, 28, 33\r<BR>\n" );
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document.write( "If you add these ten terms, your sum will be 105.\r<BR>\n" );
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