document.write( "Question 1011056: Joseph and Mikky are both studying for an exam. They feel that Joseph has a 55% chance of getting an A, and Mikky has a 35% chance. Suppose that there is a 15% chance that BOTH get an A. What is the chance that at least ONE of them will get an A? \n" ); document.write( "
Algebra.Com's Answer #626605 by Theo(13342) You can put this solution on YOUR website! probability of A or B is equal to probability of A plus probability of B minus probability of A and B.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "event A is Joseph gets an A. \n" ); document.write( "event B is Mikky gets an A.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(A) = .55 \n" ); document.write( "p(B) = .35 \n" ); document.write( "p(A and B) = .15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(A or B) = p(A) + p(B) - p(A and B).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that becomes p(A or B) = .55 + .35 - .15 = .75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "there is a 75% chance that either Joseph or Mikky gets an A or both get an A.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |