document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010239>Question 1010239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the formula N = Pe^kt, N is the number of items in terms of an initial population P at a given time t and k is a growth constant equal to the percent of growth per unit time. How long will it take for the population of a certain country to double if its annual growth rate is 8.6%? Round to the nearest year. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626552 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626552\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From N = Pe^kt, we plug in, knowing we want to double our initial P, and get<BR>\n" );
document.write( "2P = Pe^(.086t)<BR>\n" );
document.write( "and solve for t...<BR>\n" );
document.write( "2 = e^(.086t)<BR>\n" );
document.write( "ln 2 = .086t<BR>\n" );
document.write( "t = ln 2 / .086 = 8.06 years or about 8 years </SPAN>\n" );
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