document.write( "Question 1011006: Carol has $8,000 invested in two mutual funds. One fund pays an interest rate of 2.7%, and the other pays an interest rate of 3.1%. Carol received a total of $226.00 in interest. How much is invested in each account? \n" ); document.write( "
Algebra.Com's Answer #626538 by fractalier(6550)\"\" \"About 
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Call the amount invested at 2.7%, x.
\n" ); document.write( "Then the amount invested at 3.1% is 8000-x.
\n" ); document.write( "The set up looks like this:
\n" ); document.write( ".027x + .031(8000-x) = 226
\n" ); document.write( ".027x + 248 - .031x = 226
\n" ); document.write( "-.004x = -22
\n" ); document.write( "x = 22/.004 = $5500 invested at 2.7% and then
\n" ); document.write( "8000-x = $2500 at 3.1%
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