document.write( "Question 1011006: Carol has $8,000 invested in two mutual funds. One fund pays an interest rate of 2.7%, and the other pays an interest rate of 3.1%. Carol received a total of $226.00 in interest. How much is invested in each account? \n" ); document.write( "
Algebra.Com's Answer #626538 by fractalier(6550) You can put this solution on YOUR website! Call the amount invested at 2.7%, x. \n" ); document.write( "Then the amount invested at 3.1% is 8000-x. \n" ); document.write( "The set up looks like this: \n" ); document.write( ".027x + .031(8000-x) = 226 \n" ); document.write( ".027x + 248 - .031x = 226 \n" ); document.write( "-.004x = -22 \n" ); document.write( "x = 22/.004 = $5500 invested at 2.7% and then \n" ); document.write( "8000-x = $2500 at 3.1% \n" ); document.write( " |