document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1011001>Question 1011001</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a sphere is inscribed within a cube, and the radius of the sphere is 3 ft., then what is the volume inside of the cube, but outside of the sphere?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626529 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the radius is 3 feet, then the side of the cube is 6 feet.<BR>\n" );
document.write( "Then the volume inside of the cube, but outside of the sphere,<BR>\n" );
document.write( "V = V(cube) - V(sphere) =<BR>\n" );
document.write( "V = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E3+-+%284%2F3%29%28pi%29%28r%5E3%29 ALIGN=MIDDLE  ALT=\"s%5E3+-+%284%2F3%29%28pi%29%28r%5E3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > =<BR>\n" );
document.write( "V = 216 - (4/3)(pi)(27) =<BR>\n" );
document.write( "V = 216 - 36(pi) cubic feet = about 103 cubic feet </SPAN>\n" );
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