document.write( "Question 1010983: find the equation of circle passing through the points of intersection of the lines x + 3y=0 and 2x- 7y = 0 and whose center is point of intersection lines x + y +1=0 and x-2y +4=0 \n" ); document.write( "
Algebra.Com's Answer #626514 by MathLover1(20850)\"\" \"About 
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find the equation of circle passing through the points of intersection of the lines
\n" ); document.write( "\"x+%2B+3y=0\"
\n" ); document.write( "\"2x-+7y+=+0\"
\n" ); document.write( "--------------find intersection point
\n" ); document.write( "\"x+%2B+3y=0\"
\n" ); document.write( "\"x+=-3y\"
\n" ); document.write( "substitute in
\n" ); document.write( "\"2x-+7y+=+0\"
\n" ); document.write( "\"2%28-3y%29-+7y+=+0\"
\n" ); document.write( "\"-6y-+7y+=+0\"
\n" ); document.write( "\"-13y+=+0+\"
\n" ); document.write( "\"y=0\"\r
\n" ); document.write( "\n" ); document.write( "=>\"x=0\"\r
\n" ); document.write( "\n" ); document.write( "intersection point is at (\"0\",\"0\")\r
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\n" ); document.write( "\n" ); document.write( "and whose center is point of intersection lines
\n" ); document.write( "\"x+%2B+y+%2B1=0\"
\n" ); document.write( "\"x-2y+%2B4=0\"
\n" ); document.write( "----------------------------subtract
\n" ); document.write( "\"x+%2B+y+%2B1-x-%28-2y%29-4=0+\"
\n" ); document.write( " \"y+%2B1%2B2y-4=0\"
\n" ); document.write( " \"3y+-3=0\"
\n" ); document.write( "\"3y=3\"
\n" ); document.write( "\"y=1\"\r
\n" ); document.write( "\n" ); document.write( "then \"x+%2B+1+%2B1=0+\"=>\"x+%2B2=0\" =>\"x+=-2\"\r
\n" ); document.write( "\n" ); document.write( "so, if the center of the circle is at (\"-2\",\"1\") =(\"h\",\"k\") and circle passes through (\"0\",\"0\") , its radius will be the distance between these two points \r
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Solved by pluggable solver: Distance Formula

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\n" ); document.write( " The first point is (x1,y1). The second point is (x2,y2)
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\n" ); document.write( " Since the first point is (0, 0), we can say (x1, y1) = (0, 0)
\n" ); document.write( " So \"x%5B1%5D+=+0\", \"y%5B1%5D+=+0\"
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\n" ); document.write( " Since the second point is (-2, 1), we can also say (x2, y2) = (-2, 1)
\n" ); document.write( " So \"x%5B2%5D+=+-2\", \"y%5B2%5D+=+1\"
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\n" ); document.write( " Put this all together to get: \"x%5B1%5D+=+0\", \"y%5B1%5D+=+0\", \"x%5B2%5D+=+-2\", and \"y%5B2%5D+=+1\"
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\n" ); document.write( " --------------------------------------------------------------------------------------------
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\n" ); document.write( " Now use the distance formula to find the distance between the two points (0, 0) and (-2, 1)
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\n" ); document.write( " \"d+=+sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2+%2B+%28y%5B1%5D+-+y%5B2%5D%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%28%280+-+%28-2%29%29%5E2+%2B+%280+-+1%29%5E2%29\" Plug in \"x%5B1%5D+=+0\", \"y%5B1%5D+=+0\", \"x%5B2%5D+=+-2\", and \"y%5B2%5D+=+1\"
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\n" ); document.write( " \"d+=+sqrt%28%280+%2B+2%29%5E2+%2B+%280+-+1%29%5E2%29\"
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\n" ); document.write( "
\n" ); document.write( " \"d+=+sqrt%28%282%29%5E2+%2B+%28-1%29%5E2%29\"
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\n" ); document.write( " \"d+=+sqrt%284+%2B+1%29\"
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\n" ); document.write( " \"d+=+sqrt%285%29\"
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\n" ); document.write( " \"d+=+2.23606797749979\"
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\n" ); document.write( " ==========================================================
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\n" ); document.write( " Answer:
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\n" ); document.write( " The distance between the two points (0, 0) and (-2, 1) is exactly \"sqrt%285%29\" units
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\n" ); document.write( " The approximate distance between the two points is about 2.23606797749979 units
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\n" ); document.write( " So again,
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\n" ); document.write( " Exact Distance: \"sqrt%285%29\" units
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\n" ); document.write( " Approximate Distance: \"2.23606797749979\" units
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\n" ); document.write( "\n" ); document.write( "so, we have \"h=-2\",\"k=1\" and \"r=sqrt%285%29\" and the equation of your circle is:\r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2%2B%28y-1%29%5E2=5\"\r
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\n" ); document.write( "\n" ); document.write( " \r
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