document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010965>Question 1010965</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each system of equations by substitution<BR>\n" );
document.write( "x-y=3<BR>\n" );
document.write( "x-y^2=1<BR>\n" );
document.write( "The answers are (5,2)and (2,-1) but I need a step by step of how to get them, I can't seem to do it.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626479 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626479\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can do this.  Solve the linear equation for x or y, and substitute into the quadratic equation.  You will find two solutions.\r<BR>\n" );
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document.write( "Another way:  Solve the quadratic for x in terms of y.  Substitute this into the linear equation and solve for the two possible y values.  Find the corresponding x values. </SPAN>\n" );
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