document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010948>Question 1010948</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are 2 friends.  One's age is 4 years older than half his friend's age.  Together their ages are 28.  How old are they?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626452 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626452\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 friends, we'll call the x and y<BR>\n" );
document.write( "x= 1/2y+4 We'll use this value for x next:<BR>\n" );
document.write( "x+y= 28 Substitute:<BR>\n" );
document.write( "1/2y+4+y= 28 Multiply both sides times 2<BR>\n" );
document.write( "y+8+2y= 56 Add y on left and subtract 8 on both sides<BR>\n" );
document.write( "3y= 48 divide both sides by 3<BR>\n" );
document.write( "y= 16 And the problem says that x is:<BR>\n" );
document.write( "x= 1/2y+4; x= 1/2(16)+4; x= 8+4; x= 12<BR>\n" );
document.write( "One friend is 16 and the other 12<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "16+12= 28 just like the problem says. </SPAN>\n" );
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