document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010903>Question 1010903</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of 1/3 of the smaller of two numbers and 2/3 of the larger is 34. Also, 1/2 of the smaller number is equal to 1/4 of the larger. find the numbers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626428 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626428\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the smaller and the larger numbers, x and y.  Then we have<BR>\n" );
document.write( "(1/3)x + (2/3)y = 34<BR>\n" );
document.write( "and<BR>\n" );
document.write( "(1/2)x = (1/4)y  which also means 2x = y<BR>\n" );
document.write( "Let's multiply the top equation by 3 to clear fractions and get<BR>\n" );
document.write( "x + 2y = 102<BR>\n" );
document.write( "Now substitute y = 2x and get<BR>\n" );
document.write( "x + 2(2x) = 102<BR>\n" );
document.write( "x + 4x = 102<BR>\n" );
document.write( "5x = 102<BR>\n" );
document.write( "x = 20.4<BR>\n" );
document.write( "y = 2(20.4) = 40.8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );