document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010875>Question 1010875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose the mean weight of 32 ounce box of cereal is normally distributed with a mean of 32.2 ounces and standard deviation of 0.1 ounces.\r<BR>\n" );
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document.write( "A) what percentage of boxes will weigh more than 32.0 ounces, more than 32.2 ounces and between 31.0 and 32.2 ounces?\r<BR>\n" );
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document.write( "b) if one took random sample of 9 from these cereal boxes, what is the probability that the mean weight of nine sampled boxes would weigh less that 32.0 ounces </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626406 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626406\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mean 32.2<BR>\n" );
document.write( "sd=0.1<BR>\n" );
document.write( "z for 32 oz=(32-32.2)/0.1=-0.2/0.1=-2<BR>\n" );
document.write( "It is the probability the z score is >=-2 or 0.9772<BR>\n" );
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document.write( "More than 32.2 oz is 50%<BR>\n" );
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document.write( "Between 31.0 and 32.2 ounces is <BR>\n" );
document.write( "a z-score of -12 and a z-score of 0.  That is 50% as well.  <BR>\n" );
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document.write( "z-score here is (32.0-32.2)/0.1/sqrt (9)<BR>\n" );
document.write( "That is 3(-2)=-6 and the probability is essentially zero. </SPAN>\n" );
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