document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010892>Question 1010892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1 mol of carbon-12 contains 6.022 x 1023 carbon-12 atoms with a mass of 12 g.<BR>\n" );
document.write( "A.	Calculate the mass of one carbon-12 atom. Express your answer using scientific notation.<BR>\n" );
document.write( "B.	Calculate the number of carbon-12 atoms in 20.0 g of carbon-12.<BR>\n" );
document.write( "C.	Calculate the number of moles of carbon-12 atoms in 20.0 g of carbon-12.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626404 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626404\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12 gm/6.022*10^23 = x gm/1<BR>\n" );
document.write( "6.022*10^23atoms=12 gm<BR>\n" );
document.write( "1 atom=12/6.022 x!0^23=<BR>\n" );
document.write( "1.993*10^-23 gm/C atom<BR>\n" );
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document.write( "20/12*{6.022 x !0^23)=10.037 x 10^23 atoms=1.0037 x 10^24 atoms<BR>\n" );
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document.write( "That is 5/3 moles.\r<BR>\n" );
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