document.write( "Question 1009190: In triangle ABC, angle A=30° and angle C=90°. If the length of BC is five more than one-fourth of AB, find the length of the longer leg of the triangle. \n" ); document.write( "

Algebra.Com's Answer #626386 by fractalier(6550) $\"\"$ $\"About$

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In such a 30-60-90 right triangle, the side opposite the 30 degree angle is half the hypotenuse. That side is BC here. So if we call the hypotenuse AB, x, then
\n" ); document.write( "(1/4)x + 5 = (1/2)x
\n" ); document.write( "5 = (1/4)x
\n" ); document.write( "x = 20 = AB
\n" ); document.write( "BC = 10 and
\n" ); document.write( "AC, the longer leg, is 10*sqrt(3).
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