document.write( "Question 1009442: Physics: Pendulum. The period left-parenthesis Upper T ⁢ right-parenthesis of a pendulum is related to the length left-parenthesis Upper L right-parenthesis of the pendulum and the acceleration due to gravity left-parenthesis g right-parenthesis by the formula Upper T equals 2 pi StartRoot StartFraction Upper L Over g EndFraction EndRoot. If gravity is 32 ft/s2 and the period is 2 seconds, find the approximate length of the pendulum. (Note: 12 in equals 1 ft)\r
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Algebra.Com's Answer #626384 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
The formula for the period of a simple pendulum is
\n" ); document.write( "\"T+=+2%28pi%29%2Asqrt%28L%2Fg%29\"
\n" ); document.write( "Now we plug in to find L...
\n" ); document.write( "\"2+=+2%28pi%29%2Asqrt%28L%2F32%29\"
\n" ); document.write( "\"1%2F%28pi%29+=+sqrt%28L%2F32%29\"
\n" ); document.write( "\"1%2F%28pi%29%5E2+=+L%2F32\"
\n" ); document.write( "\"L+=+32%2F%28pi%29%5E2\"
\n" ); document.write( "= 3.24 feet
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