document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010717>Question 1010717</A>: <I><SPAN STYLE=\"word-break: break-all;\"> identify the conic section if it is a parabola give the vertex if it is a circle give the center and radius if it is a ellipse or a hyperbola give the center and foci <BR>\n" );
document.write( "y^2-3x+10y+37=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626382 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  identify the conic section if it is a parabola give the vertex if it is a circle give the center and radius if it is a ellipse or a hyperbola give the center and foci <BR>\n" );
document.write( "y^2-3x+10y+37=0 <BR>\n" );
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document.write( "3x = y^2+10y+37<BR>\n" );
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document.write( "x = (1/3)(y^2+10y+37)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Vertex occurs when y = -b/(2a) = -(10/3)/(2(1/3)) = -5<BR>\n" );
document.write( "Then x = (1/3)(25-50+37) = (1/3)(12) = 4<BR>\n" );
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document.write( "Vertex (4,-5)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );