document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009173>Question 1009173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a boy is 0.25 age of his father, after 8 years the sum of both ages is 61. now what is the age of father? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626371 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call their ages NOW, b and f.  We have<BR>\n" );
document.write( "b = .25f  or 4b = f<BR>\n" );
document.write( "Then we have, in 8 years,<BR>\n" );
document.write( "b+8 + f+8 = 61<BR>\n" );
document.write( "Substituting we have<BR>\n" );
document.write( "b + 8 + 4b + 8 = 61<BR>\n" );
document.write( "5b + 16 = 61<BR>\n" );
document.write( "5b = 45<BR>\n" );
document.write( "b = 9<BR>\n" );
document.write( "f = 36 years old </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );