document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010865>Question 1010865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am solving this problem: <BR>\n" );
document.write( "Suppose that you take all of the black cards out of a standard deck of 52 cards and throughly shuffle the remaining 26 red cards. From this deck of 26 red cards you will select 2 cards, one at a time, without replacement, and record whether each card picked is a face card (king, queen, jack) or not a face card.\r<BR>\n" );
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document.write( "I would like to know: the probability that exactly one of the two cards picked is a face card, given that at least one card is a face card?\r<BR>\n" );
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document.write( "I know this is a conditional probability, but I am unsure how to go about solving because I don't know whether to treat the first pick as a face card, the second pick as a face card, or both. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626352 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose that you take all of the black cards out of a standard deck of 52 cards and throughly shuffle the remaining 26 red cards. From this deck of 26 red cards you will select 2 cards, one at a time, without replacement, and record whether each card picked is a face card (king, queen, jack) or not a face card. <BR>\n" );
document.write( "I would like to know: the probability that exactly one of the two cards picked is a face card, given that at least one card is a face card? <BR>\n" );
document.write( "I know this is a conditional probability, but I am unsure how to go about solving because I don't know whether to treat the first pick as a face card, the second pick as a face card, or both. <BR>\n" );
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document.write( "P(face|face) = P(face and face)/P(face)<BR>\n" );
document.write( "# of ways to get face and face:: 6*5<BR>\n" );
document.write( "# of random pairs = 26C2 = 13*25 = 325<BR>\n" );
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document.write( "P(face|face) = (30/325)/(6/26) = (30*26)/(325*6) = 0.4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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