document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010872>Question 1010872</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to find a turning point if you are given this expression : -2x^2+40x-600<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626348 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626348\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How to find a turning point if you are given this expression : -2x^2+40x-600<BR>\n" );
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document.write( "The \"turning point\" or vertex occurs when x = -b/(2a)<BR>\n" );
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document.write( "Your Problem::<BR>\n" );
document.write( "x = -b/(2a) = -40/(2*-2) = 10<BR>\n" );
document.write( "Then y = f(10) = -2(10)^2 + 40(10) - 600 = -200+400-600 = -400<BR>\n" );
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document.write( "Ans: Vertex is (10,-400)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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