document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010866>Question 1010866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of the longer leg of a right triangle is <BR>\n" );
document.write( "4m<BR>\n" );
document.write( " more than twice the length of the shorter leg. The length of the hypotenuse is <BR>\n" );
document.write( "6m<BR>\n" );
document.write( " more than twice the length of the shorter leg. Find the side lengths of the triangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626347 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We'll call them L, S and H for long leg, short leg, and hypotenuse:<BR>\n" );
document.write( "L= 2S+4<BR>\n" );
document.write( "H= 2S+6<BR>\n" );
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document.write( "Pythagoras:<BR>\n" );
document.write( "(2S+4)^2+S^2= (2S+6)^2<BR>\n" );
document.write( "4S+16+S^2= 4S+36 Subtract 4S+16 on both sides:<BR>\n" );
document.write( "S^2= 20 Take the square root on both sides:<BR>\n" );
document.write( "S= 4.47 This is the short leg<BR>\n" );
document.write( "L= 2(4.47)+4= 12.94 This is the long leg<BR>\n" );
document.write( "H= 2(4.47)+6= 14.94 This is the hypotenuse </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );