document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010779>Question 1010779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2.1cm more than 4 times the width. If the perimeter of the rectangle is 70.2cm, what are its dimensions?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626252 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626252\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L= 4W+2.1<BR>\n" );
document.write( "2L+2W= 70.2 Substitute for L<BR>\n" );
document.write( "2(4W+2.1)+2W= 70.2<BR>\n" );
document.write( "8W+4.2+2W= 70.2<BR>\n" );
document.write( "10W= 66<BR>\n" );
document.write( "W= 6.6 And L:<BR>\n" );
document.write( "4W+2.1= 4(6.6)+2.1= 28.5<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "2(28.5)+2(6.6)= 70.2<BR>\n" );
document.write( "57+13.2= 70.2<BR>\n" );
document.write( "70.2= 70.2 We have the correct answer.\r<BR>\n" );
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