document.write( "Question 1010774: Margaret invested $15,000 in a savings account and an IRA. The savings account yielded 3% while the IRA yielded 5%. If her total revenue was $550, how much did she invest in each? \n" ); document.write( "
Algebra.Com's Answer #626230 by addingup(3677)![]() ![]() You can put this solution on YOUR website! Savings: 0.03x \n" ); document.write( "IRA: (15000-x)*0.05 \n" ); document.write( "Put it all together: \n" ); document.write( "0.03x+(15000-x)*0.05= 550 \n" ); document.write( "0.03x+750-0.05x= 550 Subtract 750 on both sides and add/subtract x on left: \n" ); document.write( "-0.02x= -200 Now divide both sides by -0.02 and remember -/- = + \n" ); document.write( " x= 10000 _o 10,000 are invested at 3% and 15000-10000= 5000 at 5% \n" ); document.write( "-------------------------------------------------- \n" ); document.write( "Check: \n" ); document.write( "10000*0.03= 300 \n" ); document.write( "5000*0.05= 250 \n" ); document.write( "300+250= 550 We have the correct answer \n" ); document.write( " |