document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010738>Question 1010738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One bar of tin alloy is 25% pure tin and another bar is 10% pure tin. How many pounds of each alloy must be used to make 75 pounds of a new alloy which is 20% pure tin? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626201 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626201\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call x the amount of 25% alloy used.<BR>\n" );
document.write( "Then 75-x is the amount of 10% used.<BR>\n" );
document.write( "The set up looks like this:<BR>\n" );
document.write( ".25x + .10(75-x) = .20(75)<BR>\n" );
document.write( ".25x + 7.5 - .10x = 15<BR>\n" );
document.write( ".15x = 7.5<BR>\n" );
document.write( "x = 50 pounds of 25%<BR>\n" );
document.write( "75-x = 25 pounds of 10% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );