document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010736>Question 1010736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A class contributed $11.40 in dimes and quarters to a welfare fund. In all, there were 60 coins. How many coins of each kind were contributed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626197 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626197\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amounts of each coin, d and q.  Then we have<BR>\n" );
document.write( "d + q = 60   <BR>\n" );
document.write( "The value equation is<BR>\n" );
document.write( "10d + 25q = 1140  (we work in cents)<BR>\n" );
document.write( "Now multiply the top one by ten and subtract and we get<BR>\n" );
document.write( "10d + 25q = 1140<BR>\n" );
document.write( "-(10d + 10q = 600)<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "15q = 540<BR>\n" );
document.write( "q = 36 quarters<BR>\n" );
document.write( "d = 60-36 = 24 dimes </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );