document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010704>Question 1010704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a chemist has one solution that is 25% salt and 75% water, and another solution that is 10% SALT. HOW MANY LITERS OF EACH SHOULD THE CHEMIST USE TO MAKE 120 LITERS THAT IS 15% SALT </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626180 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amount of 25% salt solution used, x.<BR>\n" );
document.write( "Then the amount of 10% salt solution must be 120-x.<BR>\n" );
document.write( "The set up looks like this<BR>\n" );
document.write( ".25x + .10(120-x) = (.15)(120)<BR>\n" );
document.write( ".25x + 12 - .10x = 18<BR>\n" );
document.write( ".15x = 6<BR>\n" );
document.write( "x = 40 liters of 25%<BR>\n" );
document.write( "120-x = 80 liters of 10% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );