document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009205>Question 1009205</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Arna is twice as old as Mae. In 4 years time, she will be five -thirds  (5/3) as old as Mae. How old is both of them </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626178 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call their ages NOW, a and m.  Then we have<BR>\n" );
document.write( "a = 2m  and in four years<BR>\n" );
document.write( "a + 4 = (5/3)(m + 4)<BR>\n" );
document.write( "Substituting and solving we get<BR>\n" );
document.write( "2m + 4 = (5/3)(m + 4)<BR>\n" );
document.write( "2m + 4 = (5/3)m + 20/3<BR>\n" );
document.write( "(1/3)m = 8/3<BR>\n" );
document.write( "m = 8<BR>\n" );
document.write( "a = 16 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );