document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010233>Question 1010233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains leave the depot at the same time, one traveling east and one traveling eest. The speed of one train is 14mph slower than the other. If after 4 hours the distance between the trains is 200 miles, find the speed of each train. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626173 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rate times time equals distance.<BR>\n" );
document.write( "Call the slower train's rate, r.<BR>\n" );
document.write( "The faster one is then r+14.<BR>\n" );
document.write( "The time is 4 hours and the total distance is 200 miles.<BR>\n" );
document.write( "So we write<BR>\n" );
document.write( "4r + 4(r+14) = 200<BR>\n" );
document.write( "8r + 56 = 200<BR>\n" );
document.write( "8r = 144<BR>\n" );
document.write( "r = 18 mph<BR>\n" );
document.write( "r+14 = 32 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );