document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010628>Question 1010628</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man is five times as old as his son. in two years time he will be four times as old as his son. find their present age </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626144 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626144\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call their ages NOW, m and s.  Then<BR>\n" );
document.write( "m = 5s  and in two years<BR>\n" );
document.write( "m + 2 = 4(s + 2)<BR>\n" );
document.write( "Substitute the first into the second and get<BR>\n" );
document.write( "5s + 2 = 4s + 8<BR>\n" );
document.write( "s = 6<BR>\n" );
document.write( "m = 30 </SPAN>\n" );
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