document.write( "Question 86496: Can you help me break this down and solve? Thank you so much.\r
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document.write( "x^2 - 3x = -6x - 1 \n" );
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Algebra.Com's Answer #62612 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! x^2-3x=-6x-1 \n" ); document.write( "x^2-3x+6x+1=0 \n" ); document.write( "x^2+3x+1=0 \n" ); document.write( "using the quadratic equation we get: \n" ); document.write( " \n" ); document.write( "x=(-3+-sqrt[3^2-4*1*1])/2*1 \n" ); document.write( "x=(-3+-sqrt9-4])/2 \n" ); document.write( "x=(-3+-sqrt5)/2 \n" ); document.write( "x=(-3+-2.24)/2 \n" ); document.write( "x=(-3+2.24)/2 \n" ); document.write( "x=-.76/2 \n" ); document.write( "x=-38 answer. \n" ); document.write( "x=(-3-2.24)/2 \n" ); document.write( "x=-5.24/2 \n" ); document.write( "x=-2.62 answer.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |