document.write( "Question 1010631: 67.5% of the us population were born in their state of residence. in a random sample of 200 americans find the probability that:
\n" ); document.write( "a) at least 175 were born in their state of residence
\n" ); document.write( "b) exactly 150 were born in their state of residence
\n" ); document.write( "

Algebra.Com's Answer #626105 by mathmate(429)\"\" \"About 
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\n" ); document.write( "Question:
\n" ); document.write( "67.5% of the us population were born in their state of residence. in a random sample of 200 americans find the probability that:
\n" ); document.write( "a) at least 175 were born in their state of residence
\n" ); document.write( "b) exactly 150 were born in their state of residence
\n" ); document.write( "
\n" ); document.write( "Solution:
\n" ); document.write( "This question qualifies for the binomial distribution, assuming all samples are independent, and population size is large compared to sample.
\n" ); document.write( "given:
\n" ); document.write( "n=200
\n" ); document.write( "p=0.675
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\n" ); document.write( "Using Binomial Distribution
\n" ); document.write( "A. P(X>=175)
\n" ); document.write( "\"P%28X%3E=175%29=sum%28C%28n%2Cx%29%2Ap%5Ex%2A%281-p%29%5E%28n-x%29%29+for+x=175+to+200\"
\n" ); document.write( "where C(n,x)=n!/(x!(n-x)!) is the number of combination of n choose x.
\n" ); document.write( "so after summing the terms (laborious job), we get
\n" ); document.write( "P(X>=175)=5.36*10^(-11)
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\n" ); document.write( "B. P(X=150)
\n" ); document.write( "\"P%28X=150%29=C%28n%2C150%29%2Ap%5E150%2A%281-p%29%5E%2850%29=0.004432\"
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\n" ); document.write( "Using normal approximation:
\n" ); document.write( "mean=mu=np=135
\n" ); document.write( "variance=np(1-p)=43.875
\n" ); document.write( "standard deviation=sigma=sqrt(variance)=6.62382
\n" ); document.write( "Use continuity correction
\n" ); document.write( "A.
\n" ); document.write( "z=(174.5-135)/6.62382=5.9423
\n" ); document.write( "upper tail = 1.355*10^(-9)
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\n" ); document.write( "B. it is more accurate and simpler to work with the binomial distribution.
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