document.write( "Question 1010625: Cesium-142 has a half life of 50 years. If there are 20 grams now:
\n" ); document.write( "a. Fill in the equation y=ab^x
\n" ); document.write( "b. Find the growth factor (b) for this exponential function
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Algebra.Com's Answer #626071 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
You have only one datum point in the half-life information, and then a value for making a question. Why not the basic exponential decay equation like \"y=pe%5E%28-kt%29\"?\r
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\n" ); document.write( "\n" ); document.write( "Try your simpler format anyway.
\n" ); document.write( "Half-life information would seem to make \"%281%2F2%29=1%2Ab%5E50\", using a for the initial quantity of Cs-142.\r
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\n" ); document.write( "\n" ); document.write( "\"b%5E50=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28b%5E50%29%29=log%2810%2C%281%2F2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"50%2Alog%2810%2Cb%29=log%2810%2C%281%2F2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2Cb%29=%281%2F50%29log%2810%2C%281%2F2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2Cb%29=-0.0060206\"\r
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\n" ); document.write( "\n" ); document.write( "....
\n" ); document.write( "\"highlight%28b=0.986%29\"
\n" ); document.write( "The model being \"highlight%28y=a%280.986%29%5Ex%29\", using a as the initial quantity.
\n" ); document.write( "This b value is not a growth factor!! The \"growth\" is negative, not positive.\r
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\n" ); document.write( "\n" ); document.write( "Having \"twenty grams now\", you can write \"y=20%280.985%29%5Ex\".
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