document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010548>Question 1010548</A>: <I><SPAN STYLE=\"word-break: break-all;\">   2x + 5y = -1\r<BR>\n" );
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document.write( "   x + 2y = 0\r<BR>\n" );
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document.write( " can u please show me how to solve this problem step by step </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626011 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626011\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x + 5y = -1<BR>\n" );
document.write( "x + 2y = 0 On this equation, multiply both sides times 2:<BR>\n" );
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document.write( "2x+4y= 0 Now subtract this from the first equation<BR>\n" );
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document.write( "2x + 5y = -1<BR>\n" );
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document.write( "2x + 4y = 0<BR>\n" );
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document.write( "... y = -1 Now that we know y we can find the value of x. For this we can use either one of the equations, let's use the second:<BR>\n" );
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document.write( "x + 2y = 0<BR>\n" );
document.write( "x + 2(-1)= 0<BR>\n" );
document.write( "x + -2= 0<BR>\n" );
document.write( "x= 2<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "2(2) + 5(-1) = -1<BR>\n" );
document.write( "4 + -5 = -1<BR>\n" );
document.write( "-1 = -1 This equation checks out<BR>\n" );
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document.write( "x+2y = 0<BR>\n" );
document.write( "2 + 2(-1)<BR>\n" );
document.write( "2 + -2 = 0<BR>\n" );
document.write( "0 = 0 This equation also checks out. We have the correct answers<BR>\n" );
document.write( "J </SPAN>\n" );
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