document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010548>Question 1010548</A>: <I><SPAN STYLE=\"word-break: break-all;\">   2x + 5y = -1\r<BR>\n" );
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document.write( "   x + 2y = 0\r<BR>\n" );
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document.write( " can u please show me how to solve this problem step by step </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #626003 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=626003\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Step 1) Solve for x in equation 2\r<BR>\n" );
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document.write( "x+2y = 0<BR>\n" );
document.write( "x+2y-2y = 0-2y ... subtract 2y from both sides<BR>\n" );
document.write( "x = -2y\r<BR>\n" );
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document.write( "Step 2) Replace x with -2y in equation 1. Then solve for y\r<BR>\n" );
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document.write( "2x + 5y = -1<BR>\n" );
document.write( "2(-2y) + 5y = -1 ... replace x with -2y<BR>\n" );
document.write( "-4y + 5y = -1<BR>\n" );
document.write( "1y = -1<BR>\n" );
document.write( "y = -1\r<BR>\n" );
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document.write( "Step 3) Use the value of y found in step 2 to find the value of x\r<BR>\n" );
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document.write( "x = -2y<BR>\n" );
document.write( "x = -2*(-1) ... plug in y = -1<BR>\n" );
document.write( "x = 2\r<BR>\n" );
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document.write( "Final Answer: x = 2 and y = -1. The two values pair up to form the ordered pair or point (x,y) = (2,-1)\r<BR>\n" );
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document.write( "Side Note: If you graph the two original equations on the same xy plane, then you'll see two lines crossing at the point (2,-1). </SPAN>\n" );
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