document.write( "Question 1010528:  Solve the polynomial:\r
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document.write( "x^4+x^3-6x^2-14x-12=0 \n" );
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| Algebra.Com's Answer #625988 by Boreal(15235)     You can put this solution on YOUR website! x^4+x^3-6x^2-14x-12=0. Roots possible include +/- 12,6,4,3,and 2. It has one sign change, so it has one positive root. f(-x) +/-/-/+/-, so there are 3 or 1 negative roots. \n" ); document.write( "1 ;;1;;-6;;-14;;-12 \n" ); document.write( "1;;-1;;-4;;-6 synthetic division using -2 as a root or (x+2) \n" ); document.write( "now we have x^3-x^2-4x-6 \n" ); document.write( "1;;-1;;-4;;-6 try 3 \n" ); document.write( "1;;2;;2;;0. That works (x-3) \n" ); document.write( "x^2+2x+2. That has complex roots.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |