document.write( "Question 1010528: Solve the polynomial:\r
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Algebra.Com's Answer #625988 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
x^4+x^3-6x^2-14x-12=0. Roots possible include +/- 12,6,4,3,and 2. It has one sign change, so it has one positive root. f(-x) +/-/-/+/-, so there are 3 or 1 negative roots.
\n" ); document.write( "1 ;;1;;-6;;-14;;-12
\n" ); document.write( "1;;-1;;-4;;-6 synthetic division using -2 as a root or (x+2)
\n" ); document.write( "now we have x^3-x^2-4x-6
\n" ); document.write( "1;;-1;;-4;;-6 try 3
\n" ); document.write( "1;;2;;2;;0. That works (x-3)
\n" ); document.write( "x^2+2x+2. That has complex roots.\r
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