document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010513>Question 1010513</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I got this test from my teacher and I can't figure out how to write the equation. it says write the equation of the direct variation that includes the point (-6,2). I don't get how to create the equation using those points. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625965 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625965\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, direct variation looks like<BR>\n" );
document.write( "y = kx<BR>\n" );
document.write( "If you are given an x and a y, you can plug them in to find k...like this...<BR>\n" );
document.write( "2 = k(-6)<BR>\n" );
document.write( "k = -1/3<BR>\n" );
document.write( "so that your equation becomes<BR>\n" );
document.write( "y = (-1/3)x </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );