document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009963>Question 1009963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many grams of brand A coffee worth P4.00 gram must be added to 100 grams of brand B coffee worth P 7.00 per gram to produce a mixture worth P6.00 per gram? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625905 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625905\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number of grams of coffee A, x.  The set up is like this<BR>\n" );
document.write( "4x + 7(100) = 6(x + 100)<BR>\n" );
document.write( "4x + 700 = 6x + 600<BR>\n" );
document.write( "100 = 2x<BR>\n" );
document.write( "x = 50 grams </SPAN>\n" );
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