document.write( "Question 1010443: 4/3x- 1/2=0, then x= \n" ); document.write( "
Algebra.Com's Answer #625861 by Alan3354(69443)\"\" \"About 
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\"4%2F3x-+1%2F2=0\"
\n" ); document.write( "Multiply by x
\n" ); document.write( "\"4%2F3+-+x%2F2+=+0\"
\n" ); document.write( "x/2 = 4/3
\n" ); document.write( "x = 8/3\r
\n" ); document.write( "\n" ); document.write( "
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