document.write( "Question 1010423: one no. is 40 more than another.find the no. if their sum is 50 \n" ); document.write( "
Algebra.Com's Answer #625844 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let one no. be \"x\" and another no. \"y\"\r
\n" ); document.write( "\n" ); document.write( "if \"x\" is \"40\" more than \"y\", we have \"x=y%2B40\"...eq.1\r
\n" ); document.write( "\n" ); document.write( "if their sum is \"50\", we have:\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=50\"....eq.2...substitute \"x\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"y%2B40%2By=50\"......solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"2y%2B40=50\"\r
\n" ); document.write( "\n" ); document.write( "\"2y=50-40\"\r
\n" ); document.write( "\n" ); document.write( "\"2y=10\"\r
\n" ); document.write( "\n" ); document.write( "\"y=10%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y=5%29\"\r
\n" ); document.write( "\n" ); document.write( "go back to eq.1 and substitute \"5\" for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=5%2B40\"...eq.1\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=45%29\"\r
\n" ); document.write( "\n" ); document.write( "so, your numbers are: \"highlight%285%29\" and \"highlight%2845%29\"\r
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