document.write( "Question 1010400: A car is driving down the road at 10.4 m/s. All of a sudden the driver steps on the gas to make it through the intersection before the light changes. If the car accelerates uniformly at a rate of 7.50 m/s^2, how far will the car move in 2.00 seconds? \n" ); document.write( "

Algebra.Com's Answer #625826 by KMST(5328) $\"\"$ $\"About$

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With an initial speed of 10.4 m/s,
\n" ); document.write( "and a uniform acceleration of 7.50 m/s^2 for 2.00 seconds,
\n" ); document.write( "the final speed will be
\n" ); document.write( "10.4 + 2.00(7.5) = 10.4 + 15.0 = 25.4 m/s.
\n" ); document.write( "The average speed during those 2.00 seconds will be
\n" ); document.write( "(1/2)(10.4 m/s + 25.4 m/s)=(1/2)(35.8 m/s) = 17.9 m/s .
\n" ); document.write( "With that average speed, in 2.00 seconds, the distance covered would be
\n" ); document.write( "2.00(17.9 m/s) = 35.8 meters .
\n" ); document.write( "
\n" ); document.write( "WITH FANCY FORMULAS:
\n" ); document.write( "An object moving in a straight line during a time $\"t\"$ ,
\n" ); document.write( "accelerating uniformly with acceleration $\"a\"$ ,
\n" ); document.write( "from an initial velocity $\"v%5B0%5D\"$ ,
\n" ); document.write( "covers a distance
\n" ); document.write( " $\"d=v%5B0%5D%2At%2B%281%2F2%29at%5E2\"$ .
\n" ); document.write( "In this case, understanding that the units are meters for distance and seconds for time,
\n" ); document.write( " $\"system%28t=%222.00%22%2Cv=10.4%2Ca=%227.50%22%2Cd=v%5B0%5D%2At%2B%281%2F2%29at%5E2%29\"$ ---> $\"d=10.4%2A%222.00%22%2B%281%2F2%29%28%227.50%22%29%28%222.00%22%29%5E2=20.8%2B%2215.0%22=35.8\"$ \n" ); document.write( "

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